|
|
发表于 2005-5-7 10:42:38
|
显示全部楼层
证明:假设电话号码为abcdefgh,根据题意要求证明:
[((1000a+100b+10c+d)*80+1)*250+(1000e+100f+10g+h)*2-250]/2=10000000a+1000000b+100000c+10000d+1000e+100f+10g+h
则:
[((1000a+100b+10c+d)*80+1)*250+(1000e+100f+10g+h)*2-250]/2=[(1000a+100b+10c+d)*20000+250+(1000e+100f+10g+h)*2-250]/2=
[(1000a+100b+10c+d)*20000+(1000e+100f+10g+h)*2]/2=(1000a+100b+10c+d)*10000+(1000e+100f+10g+h)=10000000a+1000000b+100000c+10000d+1000e+100f+10g+h
证明成立
综上所述,所以楼主的题目并不希奇
 |
|